ソースコード
with a as(
select ORDER_NO from ORDERS
where order_date between "2023-04-01" and "2023-06-30"
),
b as(
select
*
from orders_dtl
inner join a
using(order_no)
),

c as(
select item_code,count(*) as cnt from b
group by item_code),

last_order as(
select a.item_code,max(b.order_date) as last_order from orders_dtl as a
left join orders as b
using(order_no)
group by a.item_code
),
tmp as(
select i.item_code,l.last_order,
case when c.cnt is null then 0 else c.cnt end as ORDER_QTY from item as i
left join last_order l
using(item_code)
left join c
using(item_code)
)
select ITEM_CODE,ORDER_QTY,
RANK() OVER(order by ORDER_QTY desc,last_order desc,ITEM_CODE desc) as ITEM_POPULAR_RANK
from tmp
order by ORDER_QTY desc,last_order desc,ITEM_CODE desc
提出情報
提出日時2023/08/18 14:10:08
コンテスト第8回 SQLコンテスト
問題人気順位
受験者bk_cocoa
状態 (詳細)WA
(Wrong Answer: 誤答)
メモリ使用量96 MB
メッセージ
テストケース(通過数/総数)
0/2
状態
メモリ使用量
データパターン1
WA
96 MB
データパターン2
WA
86 MB