コンテストの制限時間が終了しました。
以降も提出を行うことができますが、順位集計には反映されません。
以降も提出を行うことができますが、順位集計には反映されません。
ソースコード
with foreigner_with_order as (
select
pf_code,
nation_code,
amt,
rank () over (
partition by pf_code
order by
amt desc
) as amt_order
from
foreigner
where
nation_code <> '113'
),
merge_all as (
select
f.pf_code,
p.pf_name,
n.nation_name,
f.amt,
f.amt_order
from
foreigner_with_order as f
inner join nationality as n on f.nation_code = n.nation_code
inner join prefecture as p on f.pf_code = p.pf_code
)
select
sub.pf_code as "都道府県コード",
sub.pf_name as "都道府県名",
(
select
m.nation_name
from
merge_all as m
where
sub.pf_code = m.pf_code
and m.amt_order = 1
) as "1位 国名",
(
select
m.amt
from
merge_all as m
where
sub.pf_code = m.pf_code
and m.amt_order = 1
) as "1位 人数",
(
select
m.nation_name
from
merge_all as m
where
sub.pf_code = m.pf_code
and m.amt_order = 2
) as "2位 国名",
(
select
m.amt
from
merge_all as m
where
sub.pf_code = m.pf_code
and m.amt_order = 2
) as "2位 人数",
(
select
m.nation_name
from
merge_all as m
where
sub.pf_code = m.pf_code
and m.amt_order = 3
) as "3位 国名",
(
select
m.amt
from
merge_all as m
where
sub.pf_code = m.pf_code
and m.amt_order = 3
) as "3位 人数",
(
select
sum(m.amt)
from
merge_all as m
group by
m.pf_code
having
sub.pf_code = m.pf_code
) as "合計人数"
from
(
select
distinct f.pf_code,
p.pf_name
from
foreigner as f
inner join prefecture as p on f.pf_code = p.pf_code
) as sub
order by
"合計人数" desc,
"都道府県コード" asc;
提出情報
提出日時 | 2022/07/24 01:54:06 |
コンテスト | 第1回 SQLコンテスト |
問題 | 外国籍分布 |
受験者 | nnenn0 |
状態 (詳細) | WA (Wrong Answer: 誤答) |
メモリ使用量 | 80 MB |
メッセージ
テストケース(通過数/総数)
1/2
状態
メモリ使用量
データパターン1
WA
80 MB
データパターン2
AC
78 MB