select 
  s.age_code as 年齢コード,
  age_name as 年齢階層名,
  sum(SP_TIME_5) as '5時間未満',
  sum(SP_TIME_6) as '5時間以上6時間未満',
  sum(SP_TIME_7) as '6時間以上7時間未満',
  sum(SP_TIME_8) as '7時間以上8時間未満',
  sum(SP_TIME_9) as '8時間以上9時間未満',
  sum(SP_TIME_9OVER) as '9時間以上'
from sleep_time_dtl as s
join age_grp as a on a.age_code = s.age_code
where pf_code in ('01000', '02000', '03000', '04000', '07000')
group by s.age_code
order by s.age_code