SELECT
    m.pf_code as "都道府県コード",
    m.pf_name as "都道府県名",
    MAX(CASE WHEN ranking = 1 THEN nation_name END) as "1位 国名",
    SUM(CASE WHEN ranking = 1 THEN amt ELSE 0 END) as "1位 人数",
    MAX(CASE WHEN ranking = 2 THEN nation_name END) as "2位 国名",
    SUM(CASE WHEN ranking = 2 THEN amt ELSE 0 END) as "2位 人数",
    MAX(CASE WHEN ranking = 3 THEN nation_name END) as "3位 国名",
    SUM(CASE WHEN ranking = 3 THEN amt ELSE 0 END) as "3位 人数",
    SUM(amt) as "合計人数"
FROM (
    SELECT 
    f.pf_code,
    p.pf_name,
    f.amt,
    n.nation_name,
    RANK() OVER (
        PARTITION BY
            f.pf_code
        ORDER BY
            f.amt DESC,
            f.nation_code
    ) AS ranking
    FROM foreigner f
    JOIN nationality n
    ON f.nation_code=n.nation_code
    JOIN prefecture p
    ON p.pf_code=f.pf_code
    WHERE f.nation_code <> "113"
) m
GROUP BY pf_code
ORDER BY SUM(amt) DESC, pf_code;