with nyu as (
select
    *
from
    IMMIGRATION as i
    join PORT as p
    on i.PORT_CODE = p.PORT_CODE
where
    i.KIND_CODE = 110 and
    i.GROUP_CODE = 120
)
, syu as (
select
    *
from
    IMMIGRATION as i
    join PORT as p
    on i.PORT_CODE = p.PORT_CODE
where
    i.KIND_CODE = 120
    i.GROUP_CODE = 120
)
select
    nyu.PORT_CODE as 港コード,
    nyu.PORT_NAME as 港名,
    nyu.AMT as 入国者数,
    syu.AMT as 出国者数,
    nyu.AMT - syu.AMT as "差分"
from
    nyu
    join syu
    on nyu.PORT_CODE = syu.PORT_CODE
where
    nyu.AMT > syu.AMT
order by
    "差分" desc,
    港コード desc