select
A.AGE_CODE as "年齢コード",
B.AGE_NAME as "年齢階層名",
sum(A.SP_TIME_5) as "5時間未満",
sum(A.SP_TIME_6) as "5時間以上6時間未満",
sum(A.SP_TIME_7) as "6時間以上7時間未満",
sum(A.SP_TIME_8) as "7時間以上8時間未満",
sum(A.SP_TIME_9) as "8時間以上9時間未満",
sum(A.SP_TIME_9OVER) as "9時間以上"
from SLEEP_TIME_DTL as A
inner join AGE_GRP as B on A.AGE_CODE == B.AGE_CODE
where A.PF_CODE in ("01000","02000","03000","04000", "05000")
group by "年齢コード"
order by "年齢コード";