select
    s.age_code as 年齢コード
    ,MAX(a.age_name) as 年齢階層名
    ,SUM(s.sp_time_5) as "5時間未満"
    ,SUM(s.sp_time_6) as "5時間以上6時間未満"
    ,SUM(s.sp_time_7) as "6時間以上7時間未満"
    ,SUM(s.sp_time_8) as "7時間以上8時間未満"
    ,SUM(s.sp_time_9) as "8時間以上9時間未満"
    ,SUM(s.sp_time_9over) as "9時間以上"
from
    sleep_time_dtl s
    left join
    age_grp a
        on s.age_code = s.age_code
order by
    s.age_code