ソースコード
        SELECT
            IMMIGRATION.PORT_CODE AS 港コード,
            PORT.PORT_NAME AS 港名,
            ( SUM(CASE WHEN IMMIGRATION.KIND_CODE = '110' THEN IMMIGRATION.AMT ELSE 0 END) - SUM(CASE WHEN IMMIGRATION.GROUP_CODE = '110' THEN IMMIGRATION.AMT ELSE 0 END)) AS 入国者数,
            ( SUM(CASE WHEN IMMIGRATION.KIND_CODE = '120' THEN IMMIGRATION.AMT ELSE 0 END) -  SUM(CASE WHEN IMMIGRATION.GROUP_CODE = '110' THEN IMMIGRATION.AMT ELSE 0 END)) AS 出国者数,
            ( SUM(CASE WHEN IMMIGRATION.KIND_CODE = '110' THEN IMMIGRATION.AMT ELSE 0 END) - SUM(CASE WHEN IMMIGRATION.GROUP_CODE = '110' THEN IMMIGRATION.AMT ELSE 0 END)) - ( SUM(CASE WHEN IMMIGRATION.KIND_CODE = '120' THEN IMMIGRATION.AMT ELSE 0 END) - SUM(CASE WHEN IMMIGRATION.GROUP_CODE = '110' THEN IMMIGRATION.AMT ELSE 0 END)) AS 差分
            FROM IMMIGRATION INNER JOIN PORT ON IMMIGRATION.PORT_CODE = PORT.PORT_CODE
            
            GROUP BY IMMIGRATION.PORT_CODE
            HAVING (( SUM(CASE WHEN IMMIGRATION.KIND_CODE = '110' THEN IMMIGRATION.AMT ELSE 0 END) - SUM(CASE WHEN IMMIGRATION.GROUP_CODE = '110' THEN IMMIGRATION.AMT ELSE 0 END)) - ( SUM(CASE WHEN IMMIGRATION.KIND_CODE = '120' THEN IMMIGRATION.AMT ELSE 0 END) - SUM(CASE WHEN IMMIGRATION.GROUP_CODE = '110' THEN IMMIGRATION.AMT ELSE 0 END))) > 0
            --HAVING (入国者数 - 出国者数) > 0
            ORDER BY 差分 DESC, IMMIGRATION.PORT_CODE DESC;
提出情報
提出日時2022/07/20 19:11:12
コンテスト第1回 SQLコンテスト
問題港入出国者分析
受験者rs_201504_sk
状態 (詳細)WA
(Wrong Answer: 誤答)
メモリ使用量102 MB
メッセージ
テストケース(通過数/総数)
1/2
状態
メモリ使用量
データパターン1
WA
94 MB
データパターン2
AC
102 MB