select
    a.age_code as "年齢コード",
    a.age_name as "年齢階層名",
    sum(std.sp_time_5) as "5時間未満",
    sum(std.sp_time_6) as "5時間以上6時間未満",
    sum(std.sp_time_7) as "6時間以上7時間未満",
    sum(std.sp_time_8) as "7時間以上8時間未満",
    sum(std.sp_time_9) as "8時間以上9時間未満",
    sum(std.sp_time_9over) as "9時間以上"
from
    sleep_time_dtl as std
    inner join
        age_grp as a
        on a.age_code = std.age_code
where
    std.pf_code in ("01000", "02000", "03000", "04000", "07000")
group by
    std.age_code
order by
    std.age_code asc
;