select
    sd.age_code as 年齢コード,
    ag.age_name as 年齢階層名,
    sum(sd.sp_time_5) as "5時間未満",
    sum(sd.sp_time_6) as "5時間以上6時間未満",
    sum(sd.sp_time_7) as "6時間以上7時間未満",
    sum(sd.sp_time_8) as "7時間以上8時間未満",
    sum(sd.sp_time_9) as "8時間以上9時間未満",
    sum(sd.sp_time_9OVER) as "9時間以上"
from
    sleep_time_dtl as sd
left join
    age_grp as ag
on
    sd.age_code = ag.age_code
group by
    sd.age_code
having
    sd.pf_code in ("01000","02000","03000","04000","07000")
order by
    sd.age_code asc
;